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HeunT

The Heun Triconfluent function

HeunTPrime

The derivative of the Heun Triconfluent function

 

Calling Sequence

Parameters

Description

Examples

References

Calling Sequence

HeunT(α, β, γ, z)

HeunTPrime(α, β, γ, z)

Parameters

α

-

algebraic expression

β

-

algebraic expression

γ

-

algebraic expression

z

-

algebraic expression

Description

• 

The HeunT function is the solution of the Heun Triconfluent equation. Following the first reference (at the end), the equation and the conditions at the origin satisfied by HeunT are

> 

FunctionAdvisor(definition, HeunT);

HeunT⁡α,β,γ,z=DESol⁡ⅆ2ⅆz2_Y⁡z−3⁢z2+γ⁢ⅆⅆz_Y⁡z−−β+3⁢z−α⁢_Y⁡z,_Y⁡z,_Y⁡0=1,D⁡_Y⁡0=0

(1)
• 

The HeunT(α,β,γ,z) function is a local solution to Heun's Triconfluent equation, computed as a standard power series expansion around the origin, a regular point. Because the single singularity is located at ∞, this series converges in the whole complex plane.

• 

The Triconfluent Heun Equation (THE) above is obtained from the Doubleconfluent Heun Equation (DHE) through a confluence process, that is, a process where two singularities coalesce, performed by redefining parameters and taking limits. In this case the two irregular singularities of the DHE are coalesced into one irregular singularity at ∞. The resulting Heun Triconfluent equation, thus, has the structure of singularities f of the 0F1 hypergeometric equation and so can be related to the Airy functions.

• 

A special case happens when in HeunT(α,β,γ,z), the second parameter satisfies β=3⁡n+1, where n is a positive integer. In this case the nth+1, nth+2 and nth+3 coefficients form a polynomial system for the remaining parameters α and γ; when this system is identically satisfied all the subsequent coefficients cancel too and the series truncates, resulting in a polynomial form of degree n for HeunT. Remark: for n=0 this situation leads to a constant, for n=1 HeunT will also be a constant since its series expansion satisfies HeunT⁢'  at 0 = 0 and for n=2 the polynomial system for α and γ is inconsistent. So the non-trivial polynomial forms of HeunT are of degree 3≤n.

Examples

Heun's Triconfluent equation,

> 

THE≔diff⁡y⁡z,z,z=3⁢z2+γ⁢diff⁡y⁡z,z+3−β⁢z−α⁢y⁡z

THE≔ⅆ2ⅆz2y⁡z=3⁢z2+γ⁢ⅆⅆzy⁡z+3−β⁢z−α⁢y⁡z

(2)

can be transformed into another version of itself, that is, an equation with one regular and one irregular singularities respectively located at 0 and ∞ through transformations of the form

> 

z=κ⁢t,y⁡z=exp⁡12⁢t⁢κ−1⁢κ2+κ+1⁢γ+t2κ3⁢u⁡t

z=κ⁢t,y⁡z=ⅇt⁢κ−1⁢κ2+κ+1⁢t2+γ2⁢κ3⁢u⁡t

(3)

where t,u⁡t are new variables and κ6=1. Under this transformation, the HeunT parameters transform according to α -> ακ2, β -> βκ3, γ -> γκ4. These transformations form a group of six elements and imply on identities, among which you have

> 

FunctionAdvisor⁡identities,HeunT

HeunT⁡α,β,γ,z=HeunT⁡j⁢α,β,j2⁢γ,j⁢z,j3=1,HeunT⁡α,β,γ,z=HeunT⁡α,−β,γ,−z⁢ⅇz3,γ=0

(4)

When, in HeunT(α,β,γ,z), β=3⁡n+1, where n is a positive integer, the nth+1, nth+2 and nth+3 coefficients form a polynomial system for the remaining parameters α and γ. When this system is identically satisfied all the subsequent coefficients cancel too and the series truncates, resulting in a polynomial form of degree n for HeunT. For example, this is the necessary condition for a polynomial form

> 

HeunT⁡α,3⁢n+3,γ,z

HeunT⁡α,3⁢n+3,γ,z

(5)

Considering the first non-trivial case, for n=3, the function is

> 

HT≔subs⁡n=3,

HT≔HeunT⁡α,12,γ,z

(6)

So the coefficients of zm for m equal to 4, 5, and 6 in the series expansion are

> 

Q≔simplify⁡series⁡HT,z,7,size

Q≔1−12⁢α⁢z2+−γ⁢α6−32⁢z3+124⁢α2−124⁢γ2⁢α−38⁢γ⁢z4−1120⁢γ2−2⁢α⁢γ⁢α+9⁢z5+−α3720+γ2⁢α2240+−γ4+27⁢γ⁢α720−γ380⁢z6+O⁡z7

(7)
> 

c4,c5,c6≔coeff⁡Q,z,4,coeff⁡Q,z,5,coeff⁡Q,z,6

c4,c5,c6≔124⁢α2−124⁢γ2⁢α−38⁢γ,−γ2−2⁢α⁢γ⁢α+9120,−α3720+γ2⁢α2240+−γ4+27⁢γ⁢α720−γ380

(8)

solving for α and γ, requesting from solve to return using RootOf, you have

> 

_EnvExplicit≔false

_EnvExplicit≔false

(9)
> 

subs⁡ga=γ,solve⁡subs⁡γ=ga,c4,c5,c6,α,ga

α=0,γ=0,α=RootOf⁡_Z3+3622,γ=RootOf⁡_Z3+36

(10)

substituting for instance the first of these two solutions in HT we have

> 

HT_polynomial≔subs⁡1,HT

HT_polynomial≔HeunT⁡0,12,0,z

(11)

When the function admits a polynomial form, as is the case of HT_polynomial by construction, to obtain the actual polynomial of degree n (in this case n=3) use

> 

eval⁡,HeunT=HeunT:-SpecialValues:-Polynomial

1−3⁢z32

(12)

References

  

Decarreau, A.; Dumont-Lepage, M.C.; Maroni, P.; Robert, A.; and Ronveaux, A. "Formes Canoniques de Equations confluentes de l'equation de Heun". Annales de la Societe Scientifique de Bruxelles. Vol. 92 I-II, (1978): 53-78.

  

Ronveaux, A. ed. Heun's Differential Equations. Oxford University Press, 1995.

  

Slavyanov, S.Y., and Lay, W. Special Functions, A Unified Theory Based on Singularities. Oxford Mathematical Monographs, 2000.

See Also

FunctionAdvisor

Heun

HeunB

HeunC

HeunD

HeunG

hypergeom