Take the differential ring :
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| (1) |
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Compute a basis for the homomorphisms.
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Since this basis has precisely one element, there is, up to multiplication by constants, precisely one map that can be presented by an operator .
In the following example, every linear map can be presented by an operator. Thus, the dimension of all such maps will be . Since the output is a basis of these maps, it must have 6 elements.
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| (6) |