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IsMatrixShape - determine if a Matrix has a specified shape
IsVectorShape - determine if a Vector has a specified shape
Calling Sequence
IsMatrixShape(A, shape)
IsVectorShape(V, shape)
Parameters
A
-
Matrix
V
Vector
shape
name of the shape
Description
The IsMatrixShape(A, shape) function determines whether Matrix A has the specified shape. A Matrix has one of the following built-in shapes if it satisfies the listed condition:
zero
All entries are 0.
identity
All entries along the main diagonal are 1, and 0 elsewhere.
scalar
All entries along the main diagonal have the same value, and are 0 elsewhere. This shape can also be indexed, in which case the entries along the main diagonal must have the value specified by the index.
diagonal
All non-zero entries appear on the main diagonal.
constant
All entries have the same value. This shape can also be indexed, in which case all entries have the value specified by the index.
band[b], band[u,l]
If a single index is given, all non-zero entries must lie on the b sub- and super-diagonals or on the main diagonal. If two indices are given, all non-zero entries must lie on the u subdiagonals, l superdiagonals or on the main diagonal.
symmetric
The Matrix must be square and for all i and j, .
skewsymmetric, antisymmetric
hermitian
The Matrix must be square and for all i and .
skewhermitian, antihermitian
triangular
This shape may be given with the indices upper or lower. If no index is given, it defaults to triangular[upper]. A matrix is upper (lower) triangular if all the non-zero entries appear in the upper (lower) triangle. If the optional second index unit is given, all entries on the main diagonal must be 1 as well.
Hessenberg
This shape may be given with the indices upper or lower. If no index is given, it defaults to Hessenberg[upper]. A matrix is upper (lower) Hessenberg if all the non-zero entries appear in the upper (lower) triangle and first subdiagonal (superdiagonal).
Additional Shapes
Users can make additional shapes known to this routine by defining a Maple procedure. If the procedure `IsMatrixShape/myshape` is defined then the function call IsMatrixShape(M, myshape) will invoke `IsMatrixShape/myshape`(M).
If shape is not a recognized built-in or user-defined shape, this routine returns false.
If either or both of the row and column dimension of A is zero, IsMatrixShape returns true (regardless of shape).
The IsVectorShape(V, shape) function determines whether V has the specified shape. A Vector has one of the following built-in shapes if it satisfies the listed condition:
All entries must be 0.
unit
V must have exactly one non-zero entry which contains 1. This shape can also be indexed, in which case the index specifies the position where the one appears.
V must have exactly one non-zero entry. This shape can also be indexed using two values j and x, in which case the jth entry of V must contain x.
Users can make additional shapes known to this routine by defining a Maple procedure. If the procedure `IsVectorShape/myshape` is defined, then the function call IsVectorShape(V, myshape) will invoke .
If the dimension of V is 0, IsVectorShape returns true (regardless of shape).
For information regarding permissible options in Matrices and Vectors, see the Matrix and Vector constructor pages.
Examples
A Matrix M is idempotent if M . M = M
`IsMatrixShape/idempotent` := proc(M) evalb( type(M, 'Matrix'(square)) and Equal(M . M, M) ); end proc:
See Also
Matrix, MatrixOptions, Vector, VectorOptions
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